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Question

The pH of a 1010M NaOH solution is:
  1. 10
  2. 7.01
  3. 6.99
  4. 4

A
10
B
7.01
C
6.99
D
4
Solution
Verified by Toppr

At 250C, Concentration of OH ions is 107M as present in water.

But the concentration, in this case, is given as of [OH] =(107+1010)M=1.001×107

Now,
pOH=log[OH]=log(1.001×107)=7log(1.001)=70.000436.99

pH=14pOH=146.997.01

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