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Question

The pH of a solution obtained by mixing 50ml of 0.4M HCl with 50ml of 0.2M NaOH is:
  1. log2
  2. 1.0
  3. log2×101
  4. 2.0

A
log2
B
1.0
C
2.0
D
log2×101
Solution
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Millimole of HCl=50×0.4=20

Millimoles of NaOH=50×0.2=10

Millimoles of HCl left =2010=10

Volume of solution =100ml

Moles of HCl per litre =10×103×1000100=101M

pH=log(101)=1

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