The phase difference between displacement and acceleration of a particle executing simple harmonic motion is:
$\frac{π}{2} r a d$
$π$ rad
$\frac{3 π}{2}$ rad
2 $π$ rad

Question

The phase difference between displacement and acceleration of a particle executing simple harmonic motion is- dfrac-pi -2-rad  pi  rad dfrac-3pi -2- rad2 pi  rad

Toppr Admin · Accepted Answer

Let X-Asin-x3C9-t-so- a-x2212-A-x3C9-2sin-x3C9-t-A-x3C9-2sin-x3C0-x3C9-t-so- clearly phase difference is -x3C0-

The phase difference between displacement and acceleration of a particle executing simple harmonic motion is:π2radπ rad3π2rad2π rad

Let X=Asin(ωt)so, a=−Aω2sin(ωt)=Aω2sin(π+ωt)so, clearly phase difference is π

The phase difference between displacement and acceleration of a particle executing simple harmonic motion is:
$\frac{π}{2} r a d$
$π$ rad
$\frac{3 π}{2}$ rad
2 $π$ rad

Let $X = A s i n (ω t)$
so, $a = - A ω^{2} s i n (ω t) = A ω^{2} s i n (π + ω t)$
so, clearly phase difference is $π$