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>>Oscillations
>>Velocity and Acceleration in SHM
>> $The phase difference between the velocit$

Question

The phase difference between the velocity and displacement of a particle executing SHM is

A

$π / 2$ radian

B

$π$ radian

C

$2 π$ radian

D

zero

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Solution

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Correct option is A)

$x = A s i n (ω t + θ)$
$v = d x / d t = A ω c o s (ω t + θ) = - A ω s i n (ω t + θ + π / 2)$ since $c o s (π / 2 + x) = - s i n x$
Thus, phase difference is of $π / 2$

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