The phase shift of the resultant y=3sinωt+4cosωt is:
None of these
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Correct option is B)
The equations can be split up as y1=3sin(ωt) and y2=4sin(2π−ωt). The phase shift is given by, δ=tan−1(a1cosα1+a2cosα2a1sinα1+a2sinα2). Substituting the given values, we get answer as 53.130 . Hence, option B is correct.