At a particular time say t=0s
Particle has velocity +v
and thus momentum p(t=0)=+mv
Also, displacement is 0
At time t,
Particle reaches maximum height with displacement x=h
Here, velocity v=0
Now,
when particle comes back to its initial position,
Velocity is reversed i.e. v=−v
and thus,
momentum, p=−mv
So, we get graph corresponding Option D.