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Question

The phase space diagram for a ball thrown vertically up from ground is
28721_46bc9d3e999e454d8a6ad35355964bd6.png
  1. 28721_116138_85bc50cd02494c90bbf118942b21e9f0.png
  2. 28721_116139_aded6beedac4432d90bee0c81ac07464.png
  3. 28721_116140_3fb24979f2794071a23e7253f130a2aa.png
  4. 28721_116141_27bb30802a1142ffbd5e560a268b5b21.png

A
28721_116138_85bc50cd02494c90bbf118942b21e9f0.png
B
28721_116141_27bb30802a1142ffbd5e560a268b5b21.png
C
28721_116139_aded6beedac4432d90bee0c81ac07464.png
D
28721_116140_3fb24979f2794071a23e7253f130a2aa.png
Solution
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At a particular time say t=0s
Particle has velocity +v
and thus momentum p(t=0)=+mv
Also, displacement is 0
At time t,
Particle reaches maximum height with displacement x=h
Here, velocity v=0
Now,
when particle comes back to its initial position,
Velocity is reversed i.e. v=v
and thus,
momentum, p=mv
So, we get graph corresponding Option D.

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