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Relation between Different Units of Length

Question

The place value of 5 in the number $25.369$ is
$\frac{5}{10}$
$\frac{5}{100}$
$5$
$50$

A

\frac{5}{100}

B

50

C

\frac{5}{10}

D

5

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Solution

Verified by Toppr

$25.369$

In this, $5$ lies on one's place.

$∴$ Place value of $5 = 5 \times 1 = 5$

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