The plot oflogx/m against logp is a straight line inclined at an angle of 45∘. When the pressure is 0.5atm and Freundlich parameter, k is 10, the amount of solute adsorbed per gram of adsorbent will be: (log5=0.6990)
12g
5g
3g
6g
A
5g
B
6g
C
12g
D
3g
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Solution
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The Freundlich adsorption isotherm is mathematically expressed as:
xm=KP1n
It can be written in y=mx+c
logxm=1n×logP+logK
logxm=1nlog(0.5)+log(10)
Therefore, plot of logxm vs logP is a straight line with slope = 1n and intercept = log K
Thus ,1n=tanθ=tan450=1
n=1
logxm=log5−log(10)+log(10)
logxm=log5
xm=5
Hence amount of solute per gram is 5g.
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The plot oflogx/m against logp is a straight line inclined at an angle of 45∘. When the pressure is 0.5atm and Freundlich parameter, k is 10, the amount of solute adsorbed per gram of adsorbent will be: (log5=0.6990)
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