The points -2-10- -2-2- and -6-2- are the vertices ofAn equilateral triangleA right-angled isosceles triangleA scalene triangleAn obtuse triangle

Question

Toppr Admin · Accepted Answer

A-x2212-2-10-B-x2212-2-2-C-6-2-AB -xA0-x221A-x2212-2-2-2-10-x2212-2-2-8BC -xA0-x221A-x2212-2-x2212-6-2-2-x2212-2-2-8AC -xA0-x221A-x2212-2-x2212-6-2-10-x2212-2-2-x221A-128Here AB - BC and-xA0-AB2-BC2-AC2

The points (-2,10), (-2,2), and (6,2) are the vertices of
An equilateral triangle
A right-angled isosceles triangle
A scalene triangle
An obtuse triangle

$A = (- 2, 10), B = (- 2, 2), C = (6, 2)$
AB = $\sqrt{{(- 2 + 2)}^{2} + {(10 - 2)}^{2}} = 8$
BC = $\sqrt{{(- 2 - 6)}^{2} + {(2 - 2)}^{2}} = 8$
AC = $\sqrt{{(- 2 - 6)}^{2} + {(10 - 2)}^{2}} = \sqrt{128}$
Here AB = BC and $A B^{2} + B C^{2} = A C^{2}$

The points (-2,10), (-2,2), and (6,2) are the vertices ofAn equilateral triangleA right-angled isosceles triangleA scalene triangleAn obtuse triangle

A=(−2,10),B=(−2,2),C=(6,2)AB = √(−2+2)2+(10−2)2=8BC = √(−2−6)2+(2−2)2=8AC = √(−2−6)2+(10−2)2=√128Here AB = BC and AB2+BC2=AC2

The points (-2,10), (-2,2), and (6,2) are the vertices of
An equilateral triangle
A right-angled isosceles triangle
A scalene triangle
An obtuse triangle

$A = (- 2, 10), B = (- 2, 2), C = (6, 2)$
AB = $\sqrt{{(- 2 + 2)}^{2} + {(10 - 2)}^{2}} = 8$
BC = $\sqrt{{(- 2 - 6)}^{2} + {(2 - 2)}^{2}} = 8$
AC = $\sqrt{{(- 2 - 6)}^{2} + {(10 - 2)}^{2}} = \sqrt{128}$
Here AB = BC and $A B^{2} + B C^{2} = A C^{2}$