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Question

The population of a small locality was $$4000$$ in $$1979$$ and $$4500$$ in $$1981$$, By what percent had the population increase?

Solution
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Population of a small locality in $$1979 = 4000$$

Population of a small locality in $$1981 = 4500$$

So, increase in population $$= 4500 - 4000$$

$$= 500$$

Thus, percent increase in population

$$= \dfrac{500 }{ 4000} \times 100$$

$$= 50 / 4$$

We get,

$$= 12.5\%$$

Therefore, the population of the locality increased by $$12.5\%$$ in two years

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