The population of a town percent is 80000- If the annual rate of increase is 4- the population after 4 years- -use the formula-A-p- left- 1-dfrac - r - 100 - right- - n - where p is the original population-

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Toppr Admin · Accepted Answer

P-original population-80000Rate of increase r-4n-4 yearsA-P-1-r100-n-80000-xD7-1-4100-4-93588-685-x2248-93599

The population of a town at percent is $80000$ . If the annual rate of increase is $4$ , find the population after $4$ years. (use the formula: $A = p {(1 + \frac{r}{100})}^{n}$ , where $p$ is the original population)

P=original population $= 80000$
Rate of increase $r = 4$
$n = 4$ years
$A = P {(1 + \frac{r}{100})}^{n}$
$= 80000 \times {(1 + \frac{4}{100})}^{4}$
$= 93588.685$
$\approx 93599$

The population of a town at percent is 80000. If the annual rate of increase is 4, find the population after 4 years. (use the formula:A=p(1+r100)n, where p is the original population)

P=original population=80000Rate of increase r=4n=4 yearsA=P(1+r100)n=80000×(1+4100)4=93588.685≈93599

The population of a town at percent is $80000$ . If the annual rate of increase is $4$ , find the population after $4$ years. (use the formula: $A = p {(1 + \frac{r}{100})}^{n}$ , where $p$ is the original population)

P=original population $= 80000$
Rate of increase $r = 4$
$n = 4$ years
$A = P {(1 + \frac{r}{100})}^{n}$
$= 80000 \times {(1 + \frac{4}{100})}^{4}$
$= 93588.685$
$\approx 93599$