Question

The population of a town increased at the rate of $10\%$ p.a. If in the year $2011$ it was $3.2\times {10}^7$, then what will it be in the year $2012$?

• A. $4.2592\times {10}^7$
• B. $4259200$
• C. $3.52\times {10}^7$
• D. $39860000$

Answer 1

Answer: (C)

$\Rightarrow$ Population of town in the year 2011 was $3.2\times {10}^7$

$\Rightarrow$ So, $P=3.2\times {10}^7,R=10\%andn=1$

$\Rightarrow$ Population of twon in 2012 = $P(1+\frac{R}{100}{)}^n$

$\Rightarrow$ $3.2\times {10}^7\times (1+\frac{10}{100}{)}^1$

$\Rightarrow$ $3.2\times {10}^7\times \frac{110}{100}$

$\Rightarrow$ $3.52\times {10}^7$

$\therefore$ The population of town in the year 2012 is $3.52\times {10}^7$.