The population of a town is 1-76-000- If it incerease the rate of 5- per annum- what will be it-s population 2 years hence-1-94-0001-94-1041-90-4401-94-040

Question

Toppr Admin · Accepted Answer

Present Population -176000Population after 1 Year -176000-5100-xD7-176000-184800Similarly- Population after 2 Year -184800-5100-xD7-184800-194040Therefore- answer is 1-94-040-

The population of a town is $1, 76, 000$ . If it incerease at the rate of $5 %$ per annum, what will be it's population $2$ years hence.
$1, 94, 000$
$1, 94, 104$
$1, 90, 440$
$1, 94, 040$

Present Population $= 176000$

Population after 1 Year $= 176000 + \frac{5}{100} \times 176000 = 184800$
Similarly,
Population after 2 Year $= 184800 + \frac{5}{100} \times 184800 = 194040$

Therefore, answer is $1, 94, 040$ .

The population of a town is 1,76,000. If it incerease at the rate of 5% per annum, what will be it's population 2 years hence.1,94,0001,94,1041,90,4401,94,040

Present Population =176000Population after 1 Year =176000+5100×176000=184800Similarly, Population after 2 Year =184800+5100×184800=194040Therefore, answer is 1,94,040.

The population of a town is $1, 76, 000$ . If it incerease at the rate of $5 %$ per annum, what will be it's population $2$ years hence.
$1, 94, 000$
$1, 94, 104$
$1, 90, 440$
$1, 94, 040$

Present Population $= 176000$

Population after 1 Year $= 176000 + \frac{5}{100} \times 176000 = 184800$
Similarly,
Population after 2 Year $= 184800 + \frac{5}{100} \times 184800 = 194040$

Therefore, answer is $1, 94, 040$ .