Question

The position of a particle travelling along x axis is given by $x_1=t^3-9t^2+6t$ where $x_t$ is in $cm$ and $t$ is in second. Then

• A. the body comes to rest firstly at $(3-\sqrt{7})$ and then at $(3+\sqrt{7})$
• B. the total displacement of the particle in travelling from the first zero of velocity to the second zero of velocity is zero
• C. the total displacement of the particle in travelling from the first zero of velocity to the second zero of velocity is $-74cm$.
• D. the particle reverses its velocity at $(3-\sqrt{7})$ s and then at $(3+\sqrt{7})$ s and has a negative velocity for $(3-\sqrt{7})$ < t < $(3+\sqrt{7})$

Answer 1

Answer: (A), (C), (D)

$x_t=t^3-9t^2+6t$