Question

# The position of an object moving along x-axis is given by x = a + bt2, where a = 8.5 m and b = 2.5 m s−2 and t is measured in seconds. The average velocity of the object between t = 2 s and t = 4 s is

A
5 m s1
B
10 m s1
C
15 m s1
D
20 m s1
Solution
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#### Position is given as x=a+bt2=8.5+2.5t2Position at t=2 s, x2=8.5+2.5(2)2=18.5 mPosition at t=4 s, x1=8.5+2.5(4)2=48.5 mDisplacement S=x2−x1=48.5−18.5=30 mTime taken t=4−2=2 sAverage velocity Vavg=St=302=15 m/s

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