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Question

# The position x of a particle varies with time as x=at2−bt3. The acceleration of particle is zero at time T equal toab2a3ba3bZero

A
ab
B
2a3b
C
a3b
D
Zero
Solution
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#### x=at2−bt3⇒ Velocity =dxdt=2at−3bt2Acceleration=d2xdt2=ddt(2at−3b2)=2a−6btor a=2a−6btMaking a=0⇒2a=6bt⇒t=dfrac2a6b=a3b.

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