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The postulate on which the photoelectric equation is derived is :
Light is emitted only when electrons jump between orbits
Light is absorbed in quanta of energy $E = h v$
Electrons are restricted to orbits of angular momentum $n \frac{h}{2 π}$ where $n$ is an integer
Electrons are associated with wave of wavelength $λ = \frac{h}{p}$ where $p$ is momentum

A

Light is emitted only when electrons jump between orbits

B

Light is absorbed in quanta of energy

E = h v

C

Electrons are restricted to orbits of angular momentum

n \frac{h}{2 π}

where

n

is an integer

D

Electrons are associated with wave of wavelength

λ = \frac{h}{p}

where

p

is momentum

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Solution

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The correct option is B Light is absorbed in quanta of energy $E = h v$
When light of sufficiently low wavelength fall on a metal surface, electrons are ejected. This phenomenon is called the photo electric effect and can be understood in terms of the particle nature of light.
i.e. If $v$ is the frequency of light that falls on metallic surface, which eject an electron, then we can say that $E = h v$ quanta of energy is absorbed during photoelectric emission.

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