The potential at a point 0.1 m from an isolated point charge is +100 volt.
(i) Find the nature of the charge.
(ii) Calculate magnitude of the point charge.
Given
Electric potential $$= 100 volt$$
Electric potential at a point due to isolated charge $$\,V = \dfrac{{kQ}}{{{r}}}$$
here $$k= 9\times 10^9$$
Here distance of point from charge$$, r = 0.1 m$$
So according to formula,
$$100 \ volt = \dfrac{{9 \times {{10}^9}Q}}{{{({0.1m)}}}}$$
$$Or\ {\rm{ }}Q{\rm{ }} = {\rm{ }}1.11 \times {10^{ - 9}}C$$
$$Part(i)$$ Nature of chare is Positive as it produces positive potential difference at a given distance
$$Part(ii)$$ its magnitude is $$1.11 \times {10^{ - 9}}C$$