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Question

The potential at a point 0.1 m from an isolated point charge is +100 volt.

(i) Find the nature of the charge.

(ii) Calculate magnitude of the point charge.

Solution
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Given

Electric potential $$= 100 volt$$

Electric potential at a point due to isolated charge $$\,V = \dfrac{{kQ}}{{{r}}}$$

here $$k= 9\times 10^9$$

Here distance of point from charge$$, r = 0.1 m$$

So according to formula,

$$100 \ volt = \dfrac{{9 \times {{10}^9}Q}}{{{({0.1m)}}}}$$

$$Or\ {\rm{ }}Q{\rm{ }} = {\rm{ }}1.11 \times {10^{ - 9}}C$$

$$Part(i)$$ Nature of chare is Positive as it produces positive potential difference at a given distance

$$Part(ii)$$ its magnitude is $$1.11 \times {10^{ - 9}}C$$

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