The potential the origin is zero due to electric field bar-E-20hat-i-30hat-j-NC-1- - The potential point P-2m- 2m- is-100V100V -140V140V

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We know vr1-x2212-vr2-x2212-x222B-r1r2Edrvx0-x2212-vx2-x2212-x222B-0220dr-x21D2-vx2-x2212-40vy0-x2212-vy2-x2212-x222B-0230drvy2-x2212-60drtotal-xA0-v-vx2-vy2-x2212-100v

The potential at the origin is zero due to electric field $¯ E = 20^i + 30^j N C^{- 1}$ . The potential at point $P (2 m, 2 m)$ is:

$- 100 V$
$100 V$
$- 140 V$
$140 V$

We know $v_{r_{1}} - v_{r_{2}} = - \int_{r_{2}}^{r_{1}} E d r$
$v_{x_{0}} - v_{x_{2}} = - \int_{2}^{0} 20 d r$
$\Rightarrow v_{x_{2}} = - 40$
$v_{y_{0}} - v_{y_{2}} = - \int_{2}^{0} 30 d r$
$v_{y_{2}} = - 60 d r$
$t o t a l v = v_{x_{2}} + v_{y_{2}} = - 100 v$

The potential at the origin is zero due to electric field ¯E=20^i+30^jNC−1 . The potential at point P(2m,2m) is:−100V100V −140V140V

We know vr1−vr2=−∫r1r2Edrvx0−vx2=−∫0220dr⇒vx2=−40vy0−vy2=−∫0230drvy2=−60drtotal v=vx2+vy2=−100v

The potential at the origin is zero due to electric field $¯ E = 20^i + 30^j N C^{- 1}$ . The potential at point $P (2 m, 2 m)$ is:

$- 100 V$
$100 V$
$- 140 V$
$140 V$

We know $v_{r_{1}} - v_{r_{2}} = - \int_{r_{2}}^{r_{1}} E d r$
$v_{x_{0}} - v_{x_{2}} = - \int_{2}^{0} 20 d r$
$\Rightarrow v_{x_{2}} = - 40$
$v_{y_{0}} - v_{y_{2}} = - \int_{2}^{0} 30 d r$
$v_{y_{2}} = - 60 d r$
$t o t a l v = v_{x_{2}} + v_{y_{2}} = - 100 v$