The potential difference between points A and B, in a section of a circuit shown, is
5 Volt
1 Volt
10 Volt
-16Volt
A
5 Volt
B
1 Volt
C
10 Volt
D
-16Volt
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Solution
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assuming the pot at A to be zero VA−6−3−4+2−5=VB ⇒VB−VA=−16
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