Question

The potential difference between points $A$ and $D$ in the given circuit is:-

• A. $\frac{2}{3}V$
• B. $\frac{8}{9}V$
• C. $\frac{4}{3}V$
• D. $2V$

Answer 1

Answer: (A)

$\begin{array}{c}{V}_A-V_C=\frac{5}{10+5}\times 2=\frac{2}{3}V----\left(i\right)\\ V_D-V_C=\frac{10}{10+5}\times 2=\frac{4}{3}V----\left(i\right)\\ subtracing\left(i\right)from\left(ii\right)weget\\ V_D-V_C-V_A+V_C=V_{AD}=\left(\frac{4}{3}-\frac{2}{3}\right)V\\ or,V_D-V_A=V_{AD}=\frac{2}{3}V\\ \therefore V_{AD}=\frac{2}{3}V\\ Hence,optionAisthecorrectanswer.\end{array}$