The potential difference between the points $^{'} A^{'}$ and $^{'} B;$ is:

$5 V$
$4 V$
$3 V$
$2 V$

4 V

3 V

2 V

5 V

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

For the circuit shown, with $$R_{1} = 1.0\Omega, R_{2} = 2.0\Omega, E_{1} = 2\ V$$ and $$E_{2} = E_{3} = 4\ V$$, the potential difference between the points $$'a'$$ and $$'b'$$ is approximately (in $$V$$).

View Solution

In the network shown, the potential difference between

A

and

B

is :
(

R = r_{1} = r_{2} = r_{3} = 1 Ω, E_{1} = 3 V, E_{2} = 2 V, E_{3} = 1 V

)

View Solution

In the network shown the potential difference between A and B is:

(R = r_{1} = r_{2} = r_{3} = 1 Ω, E_{1} = 3 V, E_{2} = 2 V, E_{3} = 1 V)

View Solution

The symbol for a cell is

If we have two types of cells having a potential difference of 4V and 5V, how should the cells be connected in order to obtain a battery with a potential difference of 2V?

View Solution

In the network shown, find the potential difference between

A

and

B

(R = r_{1} = r_{2} = r_{3} = 1 Ω, E_{1} = 3 V, E_{2} = 2 V, E_{3} = 1 V)

View Solution

The potential difference between the points ′A′ and ′B; is:5 V4 V3 V2 V

The potential difference between the points $^{'} A^{'}$ and $^{'} B;$ is:

$5 V$
$4 V$
$3 V$
$2 V$