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Question

The potential difference between the points A and B is
12556.png
  1. 2.50 V
  2. 0.5 V
  3. 1.00 V
  4. 1.50 V

A
1.50 V
B
1.00 V
C
0.5 V
D
2.50 V
Solution
Verified by Toppr

For the first loop : 12=5i+i1
For second loop :0=7(ii1)i18i1=7i
Therefore we obtain : 12=5i+78i=478ii=12×847=2.04A
i1=78×2.04=1.79A
Thus the pd across A and B is
VAVB=(ii1)×2=0.25×2=0.5V
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