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Correct option is A)

$C=dkϵ_{0}A $

where C is capacitance, k is relative permittivity of dielectric material, $ϵ_{0}$ is permittivity of free space constant, A is area of plates and d is distance between them.

Therefore, the capacitance of parallel plates is increased by the insertion of a dielectric material. Further, the capacitance is inversely proportional to the electric field between the plates, and hence the presence of the dielectric decreases the effective electric field.

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