The potential differences of the resistance, the capacitor and the inductor are $80 V, 40 V$ and $100 V$ respectively in an $L . C . R$ circuit. The power factor of the circuit is

Question

The potential differences of the resistance, the capacitor and the inductor are

80 V, 40 V

and

100 V

respectively in an

L . C . R

circuit. The power factor of the circuit is

Toppr Admin · Accepted Answer

The potential difference across an element in a circuit is given by iX-Hence 80-iR40-iXC100-iXLPower factor of circuit-cos-x3D5-RZ-R-x221A-XL-x2212-XC-2-R2-80-x221A-100-x2212-40-2-802-0-8

The potential differences of the resistance, the capacitor and the inductor are $80 V, 40 V$ and $100 V$ respectively in an $L . C . R$ circuit. The power factor of the circuit is
$0 \cdot 4$
$1 \cdot 0$
$0 \cdot 5$
$0 \cdot 8$

The potential difference across an element in a circuit is given by $i X$ .
Hence $80 = i R$
$40 = i X_{C}$
$100 = i X_{L}$
Power factor of circuit= $c o s ϕ = \frac{R}{Z}$
$= \frac{R}{\sqrt{(X_{L} - X_{C})^{2} + R^{2}}}$
$= \frac{80}{\sqrt{(100 - 40)^{2} + 80^{2}}}$
$= 0.8$

The potential differences of the resistance, the capacitor and the inductor are 80V,40V and 100V respectively in an L.C.R circuit. The power factor of the circuit is0⋅41⋅00⋅50⋅8

The potential difference across an element in a circuit is given by iX.Hence 80=iR40=iXC100=iXLPower factor of circuit=cosϕ=RZ=R√(XL−XC)2+R2=80√(100−40)2+802=0.8

The potential differences of the resistance, the capacitor and the inductor are $80 V, 40 V$ and $100 V$ respectively in an $L . C . R$ circuit. The power factor of the circuit is
$0 \cdot 4$
$1 \cdot 0$
$0 \cdot 5$
$0 \cdot 8$

The potential difference across an element in a circuit is given by $i X$ .
Hence $80 = i R$
$40 = i X_{C}$
$100 = i X_{L}$
Power factor of circuit= $c o s ϕ = \frac{R}{Z}$
$= \frac{R}{\sqrt{(X_{L} - X_{C})^{2} + R^{2}}}$
$= \frac{80}{\sqrt{(100 - 40)^{2} + 80^{2}}}$
$= 0.8$