Solve

Guides

0

Question

- 2π
- π
- π2
- √2π

Open in App

Solution

Verified by Toppr

M=1 kg

U=4(1−cos2x)

F=−dudx

F=−4[0−(−sin2x)(2)]

F=−8sin2x N

a=−8sin2x m/sec2[∵ m=1 kg]

⇒ a≃−8(2x)

a=−16x [For small x,sinx≈x]

⇒ ω2=42

ω=4 rad /ac

T=2πw=π2sec

Was this answer helpful?

14