The potential energy of system of two equal negative point charges of 2μC each held 1 m apart in air is (k=9×109SIunit)
36J
3.6×10−3J
3.6×10−2J
3.6J
A
36J
B
3.6×10−3J
C
3.6×10−2J
D
3.6J
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Solution
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The potential energy of system is U=kq1q2r U=kq2r[q1=q2=q] or U=9×109×(2×10−6)21 or U=9×109×4×10−12 or U=3.6×10−2J
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