Question

The potential of hydrogen electrode is $$-118mV$$. The concentration of $${H}^{+}$$ in the solution is:

Answer 1

Correct option is A. $$0.01M$$

$${ \varepsilon }_{ { H }^{ + }/{ H }_{ 2 } }^{ }={ \varepsilon }_{ { H }^{ + }/{ H }_{ 2 } }^{ o }-\cfrac { 0.0592 }{ 1 } \log { \cfrac { 1 }{ { H }^{ + } } } $$

$$-0.118=0+0.0592\log { \left[ { H }^{ + } \right] } \Rightarrow log\left[ { H }^{ + } \right] =\cfrac { -0.118 }{ 0.592 } =-2\Rightarrow \left[ { H }^{ + } \right] ={ 10 }^{ -2 }M$$