Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

The power dissipated in each resistor will be :
$P_{A} = 6 W, P_{B} = 9 W$
$P_{A} = 9 W, P_{B} = 6 W$
$P_{A} = 9 W, P_{B} = 3 W$
$P_{A} = 3 W, P_{B} = 6 W$

A

P_{A} = 3 W, P_{B} = 6 W

B

P_{A} = 9 W, P_{B} = 3 W

C

P_{A} = 6 W, P_{B} = 9 W

D

P_{A} = 9 W, P_{B} = 6 W

Open in App

Solution

Verified by Toppr

The voltage across the circuit is given as 6 V.
So the power dissipated by the 4 ohms resistor is given as $P = \frac{V^{2}}{R} = \frac{6^{2}}{4} = 9 W$ . And,
the power dissipated by the 6 ohms resistor is given as $P = \frac{V^{2}}{R} = \frac{6^{2}}{6} = 6 W$ .
Hence, the power dissipated by the 4 ohms and 6 ohms resistors are 9 W and 6 W.

Was this answer helpful?

2

Similar Questions

Q1

Simplify:

9 w^{3} \times 3 w^{9}

View Solution

Q2

If A and B are two events such that

(i) P (A) = \frac{1}{3}, P (B) = \frac{1}{4} and P (A \cup B) = \frac{5}{12}, then find P (A | B) and P (B | A) . (ii) P (A) = \frac{6}{11}, P (B) = \frac{5}{11} and P (A \cup B) = \frac{7}{11}, then find P (A \cap B), P (A | B) and P (B | A) . (iii) P (A) = \frac{7}{13}, P (B) = \frac{9}{13} and P (A \cap B) = \frac{4}{13}, then find P (A | B) . (iv) P (A) = \frac{1}{2}, P (B) = \frac{1}{3} and P (A \cap B) = \frac{1}{4}, then find P (A | B), P (B | A), P (A | B) and P (A | B) .

[NCERT EXEMPLAR]

View Solution

Q3

If A and B are two events, the probability that at least one of them occurs is
(a) P(A) + P(B) – 2 P(A ∩ B)
(b) P(A) + P(B) – P(A ∩ B)
(c) P(A) + P(B) + P(A ∩ B)
(d) P(A) + P(B) + 2P(A ∩ B)

View Solution

Q4

If A and B are two events such that
(i) P (A) = 1/3, P (B) = 1/4 and P (A ∪ B) = 5/12, find P (A/B) and P (B/A).
(ii) P (A) =

\frac{6}{11},

P (B) =

\frac{5}{11}

and P (A ∪ B) =

\frac{7}{11},

find P (A ∩ B), P (A/B), P (B/A).
(iii) P (A) =

\frac{7}{13},

P (B) =

\frac{9}{13}

and P (A ∩ B) =

\frac{4}{13},

find

P (A / B) .

View Solution

Q5

Check whether the following probabilities P(A) and P(B) are consistently defined

(i) P(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0.6

(ii) P(A) = 0.5, P(B) = 0.4, P(A ∪ B) = 0.8

View Solution