Question

The pressure exerted by $6.0g$ of methane gas in $a0.03m^3$ vessel at ${129}^{\circ }C$ is :

(Atomic masses : $C=12.01,H=1.01$ and $R=8.314J{K}^{-1}mo{l}^{-1})$

• A. $215216Pa$
• B. $41648Pa$
• C. $13409Pa$
• D. $31684Pa$

Answer 1

Answer: (B)

$w\text{(given mass of methane)}=6g$

$Temperature,T=129+273=402K$

$\text{Molar mass of methane},M=12.01+4\times 1.01=16.05g$

From, ideal gas equation, $pV=nRT\Rightarrow P=\frac{nRT}{v}$ $p=\frac{6}{16.05}\times \frac{8.314\times 402}{0.03}=41648Pa$

Hence, the correct option is C.