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Standard XII
Chemistry
NCERT
Question

The pressure of H2 required to make the potential of H2 -electrode zero in pure water at 298 K is:
  1. 10−14atm
  2. 10−4atm
  3. 10−12atm
  4. 10−10atm

A
10−14atm
B
10−4atm
C
10−12atm
D
10−10atm
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Solution
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2H++2e−→H2
E=E0−0.0592nlogPH2[H+]2
In 1.0 M hydrogen ion solution with hydrogen pressure of 1 atm,
E=0−0.05922log112
E=0−0.05922log1=0−0=0
In pure water, the hydrogen ion concentration is 10−7 M,
with hydrogen pressure of P atm,
E=E0−0.0592nlogPH2[H+]2
0=0−0.05922logP(10−7)2
0=logP(10−7)2
1=P(10−7)2
P=10−14atm

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