The product of the following reaction :
$$CH_2 = CH - CCl_3 + HBr$$
A
$$CH_3 - CH (Br) - CCl_3$$
C
$$CH_2 (Br) - CH_2 - CCl_3$$
D
$$BrCH_2 - CHCl - CHCl_2$$
Correct option is B. $$CH_2 (Br) - CH_2 - CCl_3$$
Given reaction is in the presence of hydrogen bromide which means that addition of proton and bromide ion will take place in accordance with Markovnikov's rule. That is proton from HBr will get bonded to the carbon atom where more number hydrogen atoms are present and bromide ion will get bonded to stable carbo-cation.\
the final product is
$$CH_2(Br) -CH_2-CCl_3$$
Hence B is correct