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Question

The product of three consecutive numbers is always divisible by $$6$$. Verify this statement with the help of some examples.

Solution
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$$2\times 3\times 4=24$$, which is divisible by $$6$$
$$9\times 10\times 11=990$$, which is divisible by $$6$$
$$20\times 21\times 22=9240$$, which is divisible by $$6$$.
Hence the statement the product of three consecutive numbers is always divisible by $$6$$ is verified

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