The product of two rational numbers is dfrac-14-27- If one of the numbers be dfrac-7-9- the other-

Question

Toppr Admin · Accepted Answer

Let the other number be - x-According to question- -dfrac-7-9- -times x-dfrac-14-27- -Rightarrow x - -dfrac-14 -times 9-27 -times 7-Rightarrow x - -dfrac-2-3-Hence- The other number is -dfrac23-

The product of two rational numbers is $$\dfrac{-14}{27}.$$ If one of the numbers be $$\dfrac{7}{9},$$ find the other.

Let the other number be $$ x$$

According to question,
$$ \dfrac{7}{9} \times x=\dfrac{-14}{27} $$
$$\Rightarrow x = \dfrac{-14 \times 9}{27 \times 7}$$
$$\Rightarrow x = \dfrac{-2}{3}$$

Hence, The other number is $$-\dfrac23$$.

The product of two rational numbers is $$\dfrac{-14}{27}.$$ If one of the numbers be $$\dfrac{7}{9},$$ find the other.

Let the other number be $$ x$$According to question,$$ \dfrac{7}{9} \times x=\dfrac{-14}{27} $$$$\Rightarrow x = \dfrac{-14 \times 9}{27 \times 7}$$$$\Rightarrow x = \dfrac{-2}{3}$$Hence, The other number is $$-\dfrac23$$.

Let the other number be $$ x$$

According to question,
$$ \dfrac{7}{9} \times x=\dfrac{-14}{27} $$
$$\Rightarrow x = \dfrac{-14 \times 9}{27 \times 7}$$
$$\Rightarrow x = \dfrac{-2}{3}$$

Hence, The other number is $$-\dfrac23$$.