Product of
two rational numbers $$=\dfrac{18}{35}$$
One of them $$=\dfrac{-2}{5}$$
$$ \therefore
\text { Second number }=\dfrac{18}{35} \div\left(\dfrac{-2}{5}\right) $$
$$\qquad =\dfrac{18}{35} \times \dfrac{5}{-2}=\dfrac{9
\times 1}{7 \times(-1)}=\dfrac{9}{-7} $$
$$=\dfrac{-9}{7}=-1
\dfrac{2}{7} $$