The product-s- are-butyl propyl etherdipropyl etherdibutyl etherpropene - but-2ene -cis and trans- - butene

Question

Toppr Admin · Accepted Answer

A non - symmetrical ether is not usually prepared by heating a mixture of ROH and R-apos-OH in acid- A mixture of three ethers R-O-R- R-O-R-apos- and R-apos-O-R-apos- is obtained- So the products are- Pr-x2212-OH-n-x2212-BuOH-x2192-PrOBu-A-PrOPr-B-BuOBu-C-

The product(s) are:

butyl propyl ether
dipropyl ether
dibutyl ether
propene + but-2ene (cis and trans) + butene

A non - symmetrical ether is not usually prepared by heating a mixture of ROH and R'OH in acid. A mixture of three ethers R-O-R, R-O-R' and R'-O-R' is obtained. So the products are: $P r - O H + n - B u O H \to P r O B u (A) + P r O P r (B) + B u O B u (C)$

The product(s) are:butyl propyl etherdipropyl etherdibutyl etherpropene + but-2ene (cis and trans) + butene

A non - symmetrical ether is not usually prepared by heating a mixture of ROH and R'OH in acid. A mixture of three ethers R-O-R, R-O-R' and R'-O-R' is obtained. So the products are: Pr−OH+n−BuOH→PrOBu(A)+PrOPr(B)+BuOBu(C)

The product(s) are:

butyl propyl ether
dipropyl ether
dibutyl ether
propene + but-2ene (cis and trans) + butene

A non - symmetrical ether is not usually prepared by heating a mixture of ROH and R'OH in acid. A mixture of three ethers R-O-R, R-O-R' and R'-O-R' is obtained. So the products are: $P r - O H + n - B u O H \to P r O B u (A) + P r O P r (B) + B u O B u (C)$