The Quantum Hall Resistance R-H- is a fundamental constant with dimensions of resistance- If h is Planck-s constant and e the electron charge- then the dimension of R-H- is the same as-e-2-hh-2-ee-h-2-h-e-2-

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Toppr Admin · Accepted Answer

R-Pi2also E-hv-ht - -xA0-because v1tAlso P-Et-ht2also i-etSo R-he2

The Quantum Hall Resistance $R_{H}$ is a fundamental constant with dimensions of resistance. If $h$ is Planck's constant and $e$ the electron charge, then the dimension of $R_{H}$ is the same as.
$e^{2} / h$
$h^{2} / e$
$e / h^{2}$
$h / e^{2}$

$R = \frac{P}{i^{2}}$
also $E = h v = \frac{h}{t}$ , because $v \frac{1}{t}$
Also $P = \frac{E}{t} = \frac{h}{t^{2}}$
also $i = \frac{e}{t}$
So $R = \frac{h}{e^{2}}$

The Quantum Hall Resistance RH is a fundamental constant with dimensions of resistance. If h is Planck's constant and e the electron charge, then the dimension of RH is the same as.e2/hh2/ee/h2h/e2

R=Pi2also E=hv=ht , because v1tAlso P=Et=ht2also i=etSo R=he2

The Quantum Hall Resistance $R_{H}$ is a fundamental constant with dimensions of resistance. If $h$ is Planck's constant and $e$ the electron charge, then the dimension of $R_{H}$ is the same as.
$e^{2} / h$
$h^{2} / e$
$e / h^{2}$
$h / e^{2}$

$R = \frac{P}{i^{2}}$
also $E = h v = \frac{h}{t}$ , because $v \frac{1}{t}$
Also $P = \frac{E}{t} = \frac{h}{t^{2}}$
also $i = \frac{e}{t}$
So $R = \frac{h}{e^{2}}$