Question

The radionuclide $$^{11}C $$ decays according to
The maximum energy of the emitted positrons is 0.960 MeV. (a) Show that the disintegration energy Q for this process is given by
$$^{11}C \rightarrow ^{11}B + e^- + v, T_{1/2} = 20.3 min.$$
The maximum energy of the emitted positrons is 0.960. MeV (a)Show that the disintegration energy Q for this process is given by
$$ Q= (m_c - m_v -2m_c ) c^2$$
where $$m_C$$ and $$m_B$$ are the atomic masses of $$^{11}C $$ and $$^{11}B$$, re-spectively, and me is the mass of a positron. (b) Given the mass val-ues $$m_C = 11.011 434 u, m_B = 11.009 305 u$$, and $$m_e = 0.000 548 6 u$$,calculate Q and compare it with the maximum energy of the emit-ted positron given above.
(Hint: Let mC and mB be the nuclearmasses and then add in enough electrons to use the atomicmasses.)

Answer 1