The radius and slant height of a cone is 10cm and 26cm- its volume-

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Radius10cm- Slant height-l-26cm- v-h-Height-h-x221A-l2-x2212-r2-x221A-262-x2212-102-x221A-676-x2212-100-x221A-576-24cmVolume-13-x3C0-r2h-13-xD7-x3C0-xD7-10-xD7-10-xD7-24-2514-28-xA0-cm3

The radius and slant height of a cone is $10$ cm and $26$ cm, find its volume.

Radius $10$ cm, Slant height $= l = 26 c m$ , $v = ?, h = ?$
Height $= h = \sqrt{l^{2} - r^{2}} = \sqrt{26^{2} - 10^{2}} = \sqrt{676 - 100} = \sqrt{576} = 24 c m$
Volume $= \frac{1}{3} π r^{2} h = \frac{1}{3} \times π \times 10 \times 10 \times 24 = 2514.28 c m^{3}$

The radius and slant height of a cone is 10cm and 26cm, find its volume.

Radius10cm, Slant height=l=26cm, v=?,h=?Height=h=√l2−r2=√262−102=√676−100=√576=24cmVolume=13πr2h=13×π×10×10×24=2514.28 cm3

The radius and slant height of a cone is $10$ cm and $26$ cm, find its volume.

Radius $10$ cm, Slant height $= l = 26 c m$ , $v = ?, h = ?$
Height $= h = \sqrt{l^{2} - r^{2}} = \sqrt{26^{2} - 10^{2}} = \sqrt{676 - 100} = \sqrt{576} = 24 c m$
Volume $= \frac{1}{3} π r^{2} h = \frac{1}{3} \times π \times 10 \times 10 \times 24 = 2514.28 c m^{3}$