The radius of 1st orbit of H is ymathring A- then De-Broglie wavelength in the 4th orbit of He- is given by-4-pi-y mathring - A - 6-pi-y mathring - A - 8-pi-y mathring - A - 2-pi-y mathring - A -

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Toppr Admin · Accepted Answer

Rn-r1n2-zfor He- fourth orbit-xA0-r4-r1-xD7-42-2-8r1-8yWe know mvr-nh-2-x3C0-substituting values-xA0-mv8y-4h-2-x3C0-h-mv-4-x3C0-y-x3BB-xA0-

The radius of $1 s t$ orbit of $H$ is $y ˚ A$ , then De-Broglie wavelength in the $4 t h$ orbit of $H e^{+}$ is given by:
$4 π y ˚ A$
$6 π y ˚ A$
$8 π y ˚ A$
$2 π y ˚ A$

$r_{n} = r_{1} n^{2} / z$
for $H e^{+}$ fourth orbit
$r_{4} = r_{1} \times 4^{2} / 2 = 8 r_{1} = 8 y$
We know $m v r = n h / 2 π$
substituting values
$m v 8 y = 4 h / 2 π$
$h / m v = 4 π y = λ$

The radius of 1st orbit of H is y˚A, then De-Broglie wavelength in the 4th orbit of He+ is given by:4πy ˚A6πy ˚A8πy ˚A2πy ˚A

rn=r1n2/zfor He+ fourth orbit r4=r1×42/2=8r1=8yWe know mvr=nh/2πsubstituting values mv8y=4h/2πh/mv=4πy=λ

The radius of $1 s t$ orbit of $H$ is $y ˚ A$ , then De-Broglie wavelength in the $4 t h$ orbit of $H e^{+}$ is given by:
$4 π y ˚ A$
$6 π y ˚ A$
$8 π y ˚ A$
$2 π y ˚ A$

$r_{n} = r_{1} n^{2} / z$
for $H e^{+}$ fourth orbit
$r_{4} = r_{1} \times 4^{2} / 2 = 8 r_{1} = 8 y$
We know $m v r = n h / 2 π$
substituting values
$m v 8 y = 4 h / 2 π$
$h / m v = 4 π y = λ$