Question

The radius of a circle with centre O is $5$ cm (given figure). Two radii OA and OB are drawn at right angles to each other. Find the areas of the segment made by the chord AB (Take $\pi =3.14$)

Answer 1

Area of segment APB$=$Area of sector AOB$-ar.△AOB$

$=\frac{90°}{360°}\times 3.14\times 5\times 5-\frac{1}{2}\times 5\times 5=\frac{39.25}{2}-\frac{25}{2}$

$=\frac{14.25}{2}=7.125c{m}^2$

Area of major segment=area of circle$-7.125$

$=\pi r^2-7.125=3.14\times 5\times 5-7.125=71.375c{m}^2$