The radius of a cone is 3 cm and vertical height is 4 cm- Find the area of the curved surface-

Question

Toppr Admin · Accepted Answer

R-3-xA0-cm and h-4-xA0-cmLet l be the slant height of the cone- Then-l2-r2-h2l2-32-42l-5-xA0-cmTherefore-Area of the curved surface - -x3C0-rl-227-xD7-3-xD7-5-47-14-xA0-cm2

The radius of a cone is 3 cm and vertical height is 4 cm. Find the area of the curved surface.

$r = 3 c m$ and $h = 4 c m$
Let $l$ be the slant height of the cone. Then,
$l^{2} = r^{2} + h^{2}$
$l^{2} = 3^{2} + 4^{2}$
$l = 5 c m$
Therefore,
Area of the curved surface = $π r l = \frac{22}{7} \times 3 \times 5 = 47.14 c m^{2}$

The radius of a cone is 3 cm and vertical height is 4 cm. Find the area of the curved surface.

r=3 cm and h=4 cmLet l be the slant height of the cone. Then,l2=r2+h2l2=32+42l=5 cmTherefore,Area of the curved surface = πrl=227×3×5=47.14 cm2

$r = 3 c m$ and $h = 4 c m$
Let $l$ be the slant height of the cone. Then,
$l^{2} = r^{2} + h^{2}$
$l^{2} = 3^{2} + 4^{2}$
$l = 5 c m$
Therefore,
Area of the curved surface = $π r l = \frac{22}{7} \times 3 \times 5 = 47.14 c m^{2}$