The radius of a conical vessel is 21 cm and the vertical height is 20 cm- What is the length of the cloth used to cover its surface- the width of the cloth is 50 cm-

Question

Toppr Admin · Accepted Answer

L-x221A-r2-h2-x221A-212-202-x221A-841-29cm-x2234- Curved surface of the vessel-xA0- Area of the cloth used-x3C0-rl-227-xD7-21-xD7-29cm2-1914cm2-x2234- length of the cloth-xA0-191450cm-38-28cm

The radius of a conical vessel is $21$ cm and the vertical height is $20$ cm. What is the length of the cloth used to cover its surface, if the width of the cloth is $50$ cm?

$l = \sqrt{r^{2} + h^{2}} = \sqrt{21^{2} + 20^{2}}$
$= \sqrt{841} = 29 c m$
$∴$ Curved surface of the vessel
= Area of the cloth used
$= π r l$
$= \frac{22}{7} \times 21 \times 29 c m^{2}$
$= 1914 c m^{2}$
$∴$ length of the cloth $= \frac{1914}{50} c m$
$= 38.28 c m$

The radius of a conical vessel is 21 cm and the vertical height is 20 cm. What is the length of the cloth used to cover its surface, if the width of the cloth is 50 cm?

l=√r2+h2=√212+202=√841=29cm∴ Curved surface of the vessel = Area of the cloth used=πrl=227×21×29cm2=1914cm2∴ length of the cloth =191450cm=38.28cm

The radius of a conical vessel is $21$ cm and the vertical height is $20$ cm. What is the length of the cloth used to cover its surface, if the width of the cloth is $50$ cm?

$l = \sqrt{r^{2} + h^{2}} = \sqrt{21^{2} + 20^{2}}$
$= \sqrt{841} = 29 c m$
$∴$ Curved surface of the vessel
= Area of the cloth used
$= π r l$
$= \frac{22}{7} \times 21 \times 29 c m^{2}$
$= 1914 c m^{2}$
$∴$ length of the cloth $= \frac{1914}{50} c m$
$= 38.28 c m$