The radius of the base of a cylinder is 20 cm and the height is 12 cm. Find the surface area of the cylinder. (Assume $π = 3.14$ ).
$4019.2 {c m}^{3}$
$4019.2 c m$
$4019.2 {c m}^{2}$
$4018.6 {c m}^{2}$

Question

The radius of the base of a cylinder is 20 cm and the height is 12 cm. Find the surface area of the cylinder. (Assume $π = 3.14$ ).
$4019.2 {c m}^{3}$
$4019.2 c m$
$4019.2 {c m}^{2}$
$4018.6 {c m}^{2}$

Toppr Admin · Accepted Answer

Surface area of cylinder is-xA0-A-2-x3C0-r-r-h-Here- radius is r-20 cm and the height is h-12 cm-Thus-A-2-x3C0-r-r-h-2-xD7-3-14-xD7-20-20-12-125-6-xD7-32-4019-2Hence- the surface area-xA0-of the cylinder is-xA0-4019-2-xA0-cm2-

The radius of the base of a cylinder is 20 cm and the height is 12 cm. Find the surface area of the cylinder. (Assume π=3.14).4019.2cm34019.2cm4019.2cm24018.6cm2

Surface area of cylinder is A=2πr(r+h)Here, radius is r=20 cm and the height is h=12 cm.Thus,A=2πr(r+h)=2×3.14×20(20+12)=125.6×32=4019.2Hence, the surface area of the cylinder is 4019.2 cm2.

The radius of the base of a cylinder is 20 cm and the height is 12 cm. Find the surface area of the cylinder. (Assume $π = 3.14$ ).
$4019.2 {c m}^{3}$
$4019.2 c m$
$4019.2 {c m}^{2}$
$4018.6 {c m}^{2}$

Surface area of cylinder is $A = 2 π r (r + h)$

Here, radius is $r = 20$ cm and the height is $h = 12$ cm.

Thus,

$A = 2 π r (r + h) = 2 \times 3.14 \times 20 (20 + 12) = 125.6 \times 32 = 4019.2$

Hence, the surface area of the cylinder is $4019.2$ cm $^{2}$ .