The radius of the base of a right circular cone is $r$ and its height is $2 h$ , then its volume is
$\frac{2}{3} π r^{2} h$
$π r^{2} h$
$2 π r^{3} h$
$\frac{1}{3} π r^{2} h$

Question

The radius of the base of a right circular cone is r and its height is 2h- then its volume isdisplaystylefrac-2-3-pi r-2hpi r-2h2pi r-3hdisplaystylefrac-1-3-pi r-2h

Toppr Admin · Accepted Answer

Given- radius -r and height -2h-xA0-Then volume of-xA0-xA0-circular-xA0-cone -13-x3C0-r2h-13-x3C0-r2-2h-23-x3C0-r2h

The radius of the base of a right circular cone is r and its height is 2h, then its volume is23πr2hπr2h2πr3h13πr2h

Given, radius =r and height =2h Then volume of circular cone =13πr2h=13πr2(2h)=23πr2h

The radius of the base of a right circular cone is $r$ and its height is $2 h$ , then its volume is
$\frac{2}{3} π r^{2} h$
$π r^{2} h$
$2 π r^{3} h$
$\frac{1}{3} π r^{2} h$

Given, radius $= r$ and height $= 2 h$
Then volume of circular cone $= \frac{1}{3} π r^{2} h$
$= \frac{1}{3} π r^{2} (2 h)$

$= \frac{2}{3} π r^{2} h$