The radius of the Moon is about one-fourth that of the Earth and acceleration due to gravity on the Moon is about one-sixth that on the Earth. From this we can conclude that the ratio of the mass of Earth in the mass of the Moon is about___________.

Question

Toppr Admin · Accepted Answer

G - GMplanetr2or Mplanet-x3B1-gr2-xA0-or mass of moon is - -mass of earth-xD7-16 -xD7- 116 - massofearth96-xA0-so- ans is B-xA0-

The radius of the Moon is about one-fourth that of the Earth and acceleration due to gravity on the Moon is about one-sixth that on the Earth. From this we can conclude that the ratio of the mass of Earth in the mass of the Moon is about___________.

10
100
1, 000
10, 000

g = $\frac{G M_{p l a n e t}}{r^{2}}$
or $M_{p l a n e t} α g r^{2}$
or mass of moon is = (mass of earth) $\times$ $\frac{1}{6}$ $\times$ $\frac{1}{16}$ = $\frac{m a s s o f e a r t h}{96}$
so, ans is B

The radius of the Moon is about one-fourth that of the Earth and acceleration due to gravity on the Moon is about one-sixth that on the Earth. From this we can conclude that the ratio of the mass of Earth in the mass of the Moon is about___________.101001, 00010, 000

g = GMplanetr2or Mplanetαgr2 or mass of moon is = (mass of earth)×16 × 116 = massofearth96 so, ans is B

The radius of the Moon is about one-fourth that of the Earth and acceleration due to gravity on the Moon is about one-sixth that on the Earth. From this we can conclude that the ratio of the mass of Earth in the mass of the Moon is about___________.

10
100
1, 000
10, 000

g = $\frac{G M_{p l a n e t}}{r^{2}}$
or $M_{p l a n e t} α g r^{2}$
or mass of moon is = (mass of earth) $\times$ $\frac{1}{6}$ $\times$ $\frac{1}{16}$ = $\frac{m a s s o f e a r t h}{96}$
so, ans is B