The rate constant disappearance of reactant as mentioned in is displaystyle 2 times 10-2- mol L-1- sec-1- the concentration of the reactant after 25 sec is 0-25M- the initial concentration is-0-75 M1-46 M0-89 M1-03 M

Question

Toppr Admin · Accepted Answer

From rate constant it can be seen that it is zero order reaction and a-x2212-x-kt- a-x-kt -0-25-2-xD7-10-x2212-2-xD7-25-0-75 M-

The rate constant for disappearance of reactant as mentioned in is $2 \times 10^{- 2} m o l L^{- 1} s e c^{- 1}$ , if the concentration of the reactant after 25 sec is 0.25M, the initial concentration is:
0.75 M
1.46 M
0.89 M
1.03 M

From rate constant it can be seen that it is zero order reaction and $a - x = k t;$ $a = x + k t$ $= 0.25 + 2 \times 10^{- 2} \times 25 = 0.75$ M.

The rate constant for disappearance of reactant as mentioned in is 2×10−2molL−1sec−1, if the concentration of the reactant after 25 sec is 0.25M, the initial concentration is:0.75 M1.46 M0.89 M1.03 M

From rate constant it can be seen that it is zero order reaction and a−x=kt; a=x+kt =0.25+2×10−2×25=0.75 M.

The rate constant for disappearance of reactant as mentioned in is $2 \times 10^{- 2} m o l L^{- 1} s e c^{- 1}$ , if the concentration of the reactant after 25 sec is 0.25M, the initial concentration is:
0.75 M
1.46 M
0.89 M
1.03 M

From rate constant it can be seen that it is zero order reaction and $a - x = k t;$ $a = x + k t$ $= 0.25 + 2 \times 10^{- 2} \times 25 = 0.75$ M.