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Question

The rate of disappearance of A in the reaction at equilibrium AB is given by :
d[A]dt=2×102[A]4×103[B] at 300 K.
The equilibrium constant Kc is :

Solution
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The rate of disappearance of A in the reaction at equilibrium AB is given by
d[A]dt=kf[A]kb[B]=2×102[A]4×103[B] at 300K.
The equilibrium constant, Kc=KfKb=2×1024×103=5

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Similar Questions
Q1
The rate of disappearance of A in the reaction at equilibrium AB is given by :
d[A]dt=2×102[A]4×103[B] at 300 K.
The equilibrium constant Kc is :
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Q2
The rate of disappearance of A at two temperature for the equilibrium AB is given by
d[A]dt=2×102[A]4×103[B] at 300 K
d[A]dt=4×1062[A]16×104[B] at 400 K
Calculate:
(i) equilibrium constants at 300 K and 400 K and
(ii) heat of reaction.
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Q3
The rate of disappearance of A at two temperature for the equilibrium AB is given by :
d[A]dt=2×102[A]4×103[B] at 300K
d[A]dt=4×102[A]16×104[B] at 400K
Calculate :
(i) equilibrium constants at 300K and 400K and
(ii) heat of reaction.

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Q4
The rate of disappearance of A at two temperature is given by: AB
I. d[A]dt=2×102[A]4×103[B] at 300 K
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Q5
Rate of disappearance of the reactant A at two different temperature is given by AB
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