0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The ratio in which the line 3x+4y+2=0 divides the distance between 3x+4y+5=0 and 3x+4y5=0 is :
  1. 7:3
  2. 3:7
  3. 2:3
  4. None of these

A
None of these
B
7:3
C
3:7
D
2:3
Solution
Verified by Toppr

Was this answer helpful?
0
Similar Questions
Q1
The ratio in which the line 3x+4y+2=0 divides the distance between 3x+4y+5=0 and 3x+4y5=0.
View Solution
Q2

The ratio in which the line 3x+4y+2=0 divides the distance between the lines 3x+4y=0 and 3x+4y5=0 is


View Solution
Q3
The ratio in which the line 3x + 4y + 2 = 0 divides the distance between the line 3x + 4y + 5 = 0 and 3x + 4y − 5 = 0 is
(a) 1: 2
(b) 3: 7
(c) 2: 3
(d) 2: 5
View Solution
Q4

The ratio in which the line 3x+4y+2=0 divides the distance between 3x+4y+5=0and 3x+4y-5=0, is


View Solution
Q5

Find the ratio in which the line 3x+4y+2=0 divides the distance between the lines 3x+4y+5=0 and 3x+4y5=0.

View Solution