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Liquefaction of Gases and Critical Constants

Question

The ratio of Boyle's temperature and critical temperature for a gas is:

A

\frac{8}{27}

B

\frac{27}{8}

C

\frac{1}{2}

D

\frac{2}{1}

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Solution

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$T_{B} = \frac{a}{b R}$

$T_{C} = \frac{8}{27} \frac{a}{b R}$

$T_{C} = \frac{8}{27} T_{B}$

$\frac{T_{B}}{T_{C}} = \frac{27}{8}$

The ratio of Boyle's temperature and critical temperature for gas is $\frac{27}{8}$ .

Hence, option B is correct.

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